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x^2-210x+3000=0
a = 1; b = -210; c = +3000;
Δ = b2-4ac
Δ = -2102-4·1·3000
Δ = 32100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32100}=\sqrt{100*321}=\sqrt{100}*\sqrt{321}=10\sqrt{321}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-210)-10\sqrt{321}}{2*1}=\frac{210-10\sqrt{321}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-210)+10\sqrt{321}}{2*1}=\frac{210+10\sqrt{321}}{2} $
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